f no es continua en 2, así que tampoco es derivable en 2

f es continua en 2, pero no es derivable en 2

f ES DERIVABLE EN 2

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f

f'

f2(x) = x
c = 0 (slider from -5 to 5, step 1)
b = 0 (slider from -5 to 5, step 1)
f1(x) = x^(2) + (b * x) + c
test2 = If(4 + (2 * b) + c ≟ 2, 0, 1)
test = If(b ≟ -3 ∧ c ≟ 4, 0, 1)
f(x) = If[x  <  2, Simplify[x^(2) + (b * x) + c], x ≥ 2, x]
A': (2, 1) / test
F: (2, 4 + (2 * b) + c) / test2
A: (2, b + 4) / test
B: (2, 2) / test
textoEc: "x²" + (If[b ≟ 0, "", If[b  <  0, "" + (If[b ≟ -1, "-", "" + b]) + "  x", "+" + (If[b ≟ 1, "", "" + b]) + "  x"]]) + (If[c ≟ 0, "", If[c  <  0, "" + c, "+" + c]])
ver = false
C = (3.32, -4.94)
texto2 = LaTeX(f, true, true)
f'(x) = If[x  <  2, Simplify[(2 * x) + b], x ≥ 2, 1]